(21x^2-3x)/2=6x1/3

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Solution for (21x^2-3x)/2=6x1/3 equation: 


x in (-oo:+oo)

(21*x^2-(3*x))/2 = (6*x^1)/3 // - (6*x^1)/3

(21*x^2-(3*x))/2-((6*x^1)/3) = 0

(21*x^2-3*x)/2-2*x = 0

(21*x^2-3*x)/2+(-2*2*x)/2 = 0

21*x^2-3*x-2*2*x = 0

21*x^2-7*x = 0

21*x^2-7*x = 0

7*x*(3*x-1) = 0

3*x-1 = 0 // + 1

3*x = 1 // : 3

x = 1/3

7*x*(x-1/3) = 0

(7*x*(x-1/3))/2 = 0

(7*x*(x-1/3))/2 = 0 // * 2

7*x*(x-1/3) = 0

( 7*x )

7*x = 0 // : 7

x = 0

( x-1/3 )

x-1/3 = 0 // + 1/3

x = 1/3

x in { 0, 1/3 }

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